컨테이너와 반복문의 만남
Python
1 2 3 4 5 | members = ['egoing', 'leezche', 'graphittie']i = 0while i < len(members): print(members[i]) i = i + 1 |
Ruby
1 2 3 4 5 6 | members = ['egoing', 'leezche', 'graphittie']i = 0while i < members.length do puts(members[i]) i = i + 1end |
실행결과
1 2 3 | egoingleezchegraphittie |
달콤한 for문의 등장
Python
1 2 3 | members = ['egoing', 'leezche', 'graphittie']for member in members: print(member) |
Ruby
1 2 3 4 | members = ['egoing', 'leezche', 'graphittie']for member in members do puts(member)end |
실행결과
1 2 3 | egoingleezchegraphitti |
for문의 활용
Python
1 2 | for item in range(5, 11): print(item) |
Ruby
1 2 3 | for item in (5..10) do puts(item)end |
실행결과
1 2 3 4 5 6 | 5678910 |
로그인 애플리케이션에 투입
Python
1 2 3 4 5 6 7 8 | input_id = input("아이디를 입력해주세요.\n")members = ['egoing', 'k8805', 'leezche']for member in members: if member == input_id: print('Hello!, '+member) import sys sys.exit()print('Who are you?') |
Ruby
1 2 3 4 5 6 7 8 9 10 | puts("아이디를 입력해주세요")input_id = gets.chomp()members = ['egoing', 'k8805', 'leezche']for member in members do if member == input_id puts('Hello!, '+member) exit endendputs('Who are you?') |
실행결과
입력 값에 따라서 달라요~
